Просмотр исходного кода

Use id to find subscription

It's the new method signature.
Alberto Fernández Capel 8 лет назад
Родитель
Сommit
66b492ba5f

+ 1 - 1
services/web/app/coffee/Features/Subscription/TeamInvitesHandler.coffee

@@ -76,7 +76,7 @@ module.exports = TeamInvitesHandler =
 			return callback(err) if err?
 			return callback(new Errors.NotFoundError('invite not found')) unless invite?
 
-			SubscriptionUpdater.addUserToGroup subscription.admin_id, userId, (err) ->
+			SubscriptionUpdater.addUserToGroup subscription._id, userId, (err) ->
 				return callback(err) if err?
 
 				removeInviteFromTeam(subscription.id, invite.email, callback)

+ 2 - 1
services/web/test/unit/coffee/Subscription/TeamInvitesHandlerTests.coffee

@@ -26,6 +26,7 @@ describe "TeamInvitesHandler", ->
 
 		@subscription = {
 			id: "55153a8014829a865bbf700d",
+			_id: new ObjectId("55153a8014829a865bbf700d"),
 			admin_id: @manager.id,
 			groupPlan: true,
 			member_ids: [],
@@ -210,7 +211,7 @@ describe "TeamInvitesHandler", ->
 
 		it "adds the user to the team", (done) ->
 			@TeamInvitesHandler.acceptInvite "dddddddd", @user.id, =>
-				@SubscriptionUpdater.addUserToGroup.calledWith(@manager.id, @user.id).should.eq true
+				@SubscriptionUpdater.addUserToGroup.calledWith(@subscription._id, @user.id).should.eq true
 				done()
 
 		it "removes the invite from the subscription", (done) ->